螺旋矩陣

#include <iostream>
#include <vector>
void display(std::vector<std::vector<int>>&nums){
       for(int i = 0; i < nums.size(); ++i){
             for(int j = 0; j < nums[0].size(); ++j){
                   std::cout<<nums[i][j]<<' ';
             }
             std::cout<<std::endl;
       }
}
void Process(int x1, int y1, int x2, int y2, std::vector<std::vector<int>>&nums){
      if(x1 == x2){
            while (y1 <= y2)
            {
                  std::cout<<nums[x1][y1++]<<' ';
            }    
      } else if(y1 == y2){
            while (x1 <= x2)
            {
                  std::cout<<nums[x1++][y1]<<' ';
            }    
      }else{
            for(int i = y1; i <= y2; ++i){
                  std::cout<<nums[x1][i]<<' ';
            }
            for(int i = x1 + 1; i <= x2; ++i){
                  std::cout<<nums[i][y2]<<' ';
            }
            for(int i = y2 - 1; i >= y1; --i){
                  std::cout<<nums[x2][i]<<' ';
            }
            for(int i = x2 - 1; i > x1; --i){
                   std::cout<<nums[i][y1]<<' ';
            }
      }
}
int main(){
    std::vector<std::vector<int>>nums;
    int n = 6;
    int m = 6;
    nums.resize(n);
    int num = 1;
    for(int i = 0; i < n;  ++i){
        std::vector<int>tmp(m, 0);
        for(int j = 0; j < m; ++j){
             tmp[j] = num++;
        }
        nums[i] = tmp;
    }
    display(nums);
    // 矩陣類型的題目可以枚舉一些特殊的點來做左上角點和右下角點, 然后在往內部收縮
    int x1 = 0, y1 = 0, x2 = n-1, y2 = m-1;
    while (x1 <= x2)
    {
        Process(x1, y1, x2, y2, nums);
        ++x1;
        ++y1;
        --x2;
        --y2;
    }
    
    std::getchar();
 

}

旋轉矩陣

類似于這個螺旋矩陣我們也是在每次處理最外層的矩形，然后往內收縮。
對于一個矩形我們選取四個點依次進行交換即可

#include <iostream>
#include <vector>
void display(std::vector<std::vector<int>>&nums){
       for(int i = 0; i < nums.size(); ++i){
             for(int j = 0; j < nums[0].size(); ++j){
                   std::cout<<nums[i][j]<<' ';
             }
             std::cout<<std::endl;
       }
}
void Process(int x1, int y1, int x2, int y2, std::vector<std::vector<int>>&nums){
      if(x1 == x2){
            while (y1 <= y2)
            {
                  std::cout<<nums[x1][y1++]<<' ';
            }    
      } else if(y1 == y2){
            while (x1 <= x2)
            {
                  std::cout<<nums[x1++][y1]<<' ';
            }    
      }else{
            for(int i = y1; i <= y2; ++i){
                  std::cout<<nums[x1][i]<<' ';
            }
            for(int i = x1 + 1; i <= x2; ++i){
                  std::cout<<nums[i][y2]<<' ';
            }
            for(int i = y2 - 1; i >= y1; --i){
                  std::cout<<nums[x2][i]<<' ';
            }
            for(int i = x2 - 1; i > x1; --i){
                   std::cout<<nums[i][y1]<<' ';
            }
      }
}
int main(){
    std::vector<std::vector<int>>nums;
    int n = 4;
    int m = 4;
    nums.resize(n);
    int num = 1;
    for(int i = 0; i < n;  ++i){
        std::vector<int>tmp(m, 0);
        for(int j = 0; j < m; ++j){
             tmp[j] = num++;
        }
        nums[i] = tmp;
    }
    display(nums);
    // 枚舉矩陣的四個點把最外圈的給調整好再往內圈收縮
    int x1, y1, x2, y2, x3, y3, x4, y4;
    int count = 0;

    while(count < n -2){
          x1 = count, y1 = count;
          x2 = count, y2 = n - 1 - count;
          x3 = n - 1 - count, y3 = count;
          x4 = n - 1 - count, y4 = n - 1 - count;
          while(y1 < y2 && x2 < x4 && y4 > y3 && x3 > x1){
                std::swap(nums[x1][y1], nums[x2][y2]);
                std::swap(nums[x1][y1], nums[x4][y4]);
                std::swap(nums[x1][y1], nums[x3][y3]);
                ++y1;
                ++x2;
                --y4;
                --x3;
                
          }
          ++count;
    }
    display(nums);
   
    
    std::getchar();
 

}

矩陣Z字打印

也是和螺旋矩陣類似選取兩個點進行循環(huán)文章來源地址http://www.zghlxwxcb.cn/news/detail-694286.html

#include <iostream>
#include <vector>
void display(int x1, int y1, int x2, int y2, std::vector<std::string>&strs){
      if(x1 < x2){
           while ( x1 <= x2 )
           {
                std::cout<<strs[x1++][y1--]<<' ';
           }
           std::cout<<std::endl;      
      } else{
           while ( x1 >= x2  )
           {
                std::cout<<strs[x1--][y1++]<<' ';
           }
           std::cout<<std::endl;          
      }
}
int main(){
     std::vector<std::string>strs = {"abcd", "efgh", "jklh"};
     int n = strs.size();
     int m = strs[0].size();
     int x1 = 0, y1 = 0;
     int x2 = 0, y2 = 0;
     int num = 0;
     while(x1 < n){
          if(num % 2 == 0){
               display(x1, y1, x2, y2, strs);
          } else{
               display(x2, y2, x1, y1, strs);
          }
          if(y1 < m - 1){
              y1++;
          }else{
              x1++;
          }
          if(x2 < n - 1){
              x2++;
          }else{
              y2++;
          }
          num++;
     } 
     std::getchar();


}

矩陣打印的題目可以從選取若干個點然后處理一層之后再往內進行收縮的做法先進行考慮

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