碼蹄集網(wǎng)站地址：https://www.matiji.net/exam/ojquestionlist
?MT1558新生命
狼群新生了一只尊貴的艾爾法狼，請設計一個結構體，管理它的信息，信息包括名字，年齡，性別。
輸入艾爾法狼寶寶的信息，然后再輸出他的信息。
格式
輸入格式：
輸入名字性別為字符型，年齡整型
輸出格式：
輸出名字性別為字符型，年齡整型
#include<stdio.h>
struct information
{
char name[50];
int age;
char sex;
} message;
int main()
{
scanf("%s %d %c", message.name, &message.age, &message.sex);
printf("%s %d %c\n", message.name, message.age, message.sex);
return 0;
}
?MT1559幼兒園
幼兒園開學了，請幫老師設計一個結構體，管理寶寶們的信息，信息包括姓名，年齡，性別。
輸入5個寶寶的信息，然后再輸出他們的信息。
格式
輸入格式：
輸入分5行，姓名性別為字符型，年齡整型
輸出格式：
輸出1行
#include<stdio.h>
struct information
{
char name[50];
int age;
char sex;
};
int main()
{
struct information baby1;
struct information baby2;
struct information baby3;
struct information baby4;
struct information baby5;
scanf("%s %d %c", baby1.name, &baby1.age, &baby1.sex);
scanf("%s %d %c", baby2.name, &baby2.age, &baby2.sex);
scanf("%s %d %c", baby3.name, &baby3.age, &baby3.sex);
scanf("%s %d %c", baby4.name, &baby4.age, &baby4.sex);
scanf("%s %d %c", baby5.name, &baby5.age, &baby5.sex);
printf("%s %d %c ", baby1.name, baby1.age, baby1.sex);
printf("%s %d %c ", baby2.name, baby2.age, baby2.sex);
printf("%s %d %c ", baby3.name, baby3.age, baby3.sex);
printf("%s %d %c ", baby4.name, baby4.age, baby4.sex);
printf("%s %d %c ", baby5.name, baby5.age, baby5.sex);
return 0;
}
?MT1562誰是先鋒
攻城戰(zhàn)要開始了，女王依依手里有4個黑騎士，女王依依要找出最強大的黑騎士作為先鋒。
請設計一個結構體，管理他們的信息，信息包括姓名，攻擊力。
輸入他們信息，然后再輸出先鋒的信息。
格式
輸入格式：
輸入分4行，姓名為字符型，攻擊力整型
輸出格式：
輸出分4行
#include<stdio.h>
struct information
{
char name[50];
int attack_power;
};
int main()
{
struct information Knight1;
struct information Knight2;
struct information Knight3;
struct information Knight4;
scanf("%s %d", Knight1.name, &Knight1.attack_power);
scanf("%s %d", Knight2.name, &Knight2.attack_power);
scanf("%s %d", Knight3.name, &Knight3.attack_power);
scanf("%s %d", Knight4.name, &Knight4.attack_power);
if ((Knight1.attack_power > Knight2.attack_power) && (Knight3.attack_power > Knight4.attack_power))
{
if (Knight1.attack_power > Knight3.attack_power)
{
printf("%s %d", Knight1.name, Knight1.attack_power);
}
else
{
printf("%s %d", Knight3.name, Knight3.attack_power);
}
}
else if ((Knight1.attack_power < Knight2.attack_power) && (Knight3.attack_power < Knight4.attack_power))
{
if (Knight2.attack_power > Knight4.attack_power)
{
printf("%s %d", Knight2.name, Knight2.attack_power);
}
else
{
printf("%s %d", Knight4.name, Knight4.attack_power);
}
}
else if ((Knight1.attack_power > Knight2.attack_power) && (Knight3.attack_power < Knight4.attack_power))
{
if (Knight1.attack_power > Knight4.attack_power)
{
printf("%s %d", Knight1.name, Knight1.attack_power);
}
else
{
printf("%s %d", Knight4.name, Knight4.attack_power);
}
}
else if ((Knight1.attack_power < Knight2.attack_power) && (Knight3.attack_power > Knight4.attack_power))
{
if (Knight2.attack_power > Knight3.attack_power)
{
printf("%s %d", Knight2.name, Knight2.attack_power);
}
else
{
printf("%s %d", Knight3.name, Knight3.attack_power);
}
}
return 0;
}
?MT1563誰是膽小鬼
攻城戰(zhàn)結束了，女王依依清點俘虜，發(fā)現(xiàn)跑掉了1個膽小的穴居人，女王依依要找出是誰跑掉了。斥候調查發(fā)現(xiàn)逃走的是一個攻擊力最弱小的穴居人。
請設計一個結構體，管理穴居人俘虜?shù)男畔?，信息包括姓名，攻擊力?/p>
輸入4個俘虜?shù)男畔?，然后再輸出逃走的俘虜?shù)男畔ⅰ?/p>
格式
輸入格式：
輸入分4行，姓名為字符型，攻擊力整型
輸出格式：
輸出分4行
#include<stdio.h>
struct information
{
char name[50];
int attack_power;
};
int main()
{
struct information people1;
struct information people2;
struct information people3;
struct information people4;
scanf("%s %d", people1.name, &people1.attack_power);
scanf("%s %d", people2.name, &people2.attack_power);
scanf("%s %d", people3.name, &people3.attack_power);
scanf("%s %d", people4.name, &people4.attack_power);
if ((people1.attack_power < people2.attack_power) && (people3.attack_power < people4.attack_power))
{
if (people1.attack_power < people3.attack_power)
{
printf("%s %d", people1.name, people1.attack_power);
}
else
{
printf("%s %d", people3.name, people3.attack_power);
}
}
else if ((people1.attack_power > people2.attack_power) && (people3.attack_power > people4.attack_power))
{
if (people2.attack_power < people4.attack_power)
{
printf("%s %d", people2.name, people2.attack_power);
}
else
{
printf("%s %d", people4.name, people4.attack_power);
}
}
else if ((people1.attack_power < people2.attack_power) && (people3.attack_power > people4.attack_power))
{
if (people1.attack_power < people4.attack_power)
{
printf("%s %d", people1.name, people1.attack_power);
}
else
{
printf("%s %d", people4.name, people4.attack_power);
}
}
else if ((people1.attack_power > people2.attack_power) && (people3.attack_power < people4.attack_power))
{
if (people2.attack_power < people3.attack_power)
{
printf("%s %d", people2.name, people2.attack_power);
}
else
{
printf("%s %d", people3.name, people3.attack_power);
}
}
return 0;
}
?MT1564編程好難
小碼哥買了3本編程書，他想先學最簡單的，請幫他把最薄的書挑出來。 請設計一個結構體，管理書籍的信息，信息包括種類，書名（不含空格），頁數(shù)。輸入書籍的信息，然后再輸出最薄的書信息。
格式
輸入格式：
按行輸入種類，書名為字符型，價格整型文章來源：http://www.zghlxwxcb.cn/news/detail-502656.html
輸出格式：
按行輸出種類，書名為字符型，價格整型文章來源地址http://www.zghlxwxcb.cn/news/detail-502656.html
#include<stdio.h>
struct Books
{
char language[10];
char name[30];
int page;
};
int main()
{
struct Books book1;
struct Books book2;
struct Books book3;
scanf("%s %s %d", book1.language, book1.name, &book1.page);
scanf("%s %s %d", book2.language, book2.name, &book2.page);
scanf("%s %s %d", book3.language, book3.name, &book3.page);
if (book1.page < book2.page && book1.page < book3.page)
{
printf("%s %s %d", book1.language, book1.name, book1.page);
}
else if (book2.page < book1.page && book2.page < book3.page)
{
printf("%s %s %d", book2.language, book2.name, book2.page);
}
else if (book3.page < book2.page && book3.page < book1.page)
{
printf("%s %s %d", book3.language, book3.name, book3.page);
}
return 0;
}
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