今天被這個方括號懵暈了，特此記錄
例如： 去除輸入字符串“1[2.3]4[ab,c]”中的所有方括號和逗號：
$ echo "1[2.3]4[ab,c]"|sed -e "s/[,\]\[]//g"
1[2.3]4[ab,c]
?
It doesn't work!
原因：Regular Expressions
The <right-square-bracket> (?']'?) shall lose its special meaning and represent itself in a bracket expression if it occurs first in the list (after an initial <circumflex> (?'^'?), if any).
解決方案：關(guān)鍵是要把 ] 右方括號不加escape放在首位.
$ echo "1[2.3]4[ab,c]"|sed -e "s/[][,]//g"
12.34abc
$ echo "1[2.3]4[ab,c]"|sed -e "s/[]\[,]//g"
12.34abc
$ echo "1[2.3]4[ab,c]"|sed -e "s/[],[]//g"
12.34abc
?
The order of some characters is important:
-
-?should be at the end like this?-] -
[]?should be like that?[][other characters] -
'?should be escaped like that?'\'' - not begin with?
^?like in?[^ - not begin with?
[.?[=?[:?and end with?.]?=]?:] - not end with?
$]
References:
regex - How to escape square closing bracket in sed - Stack Overflow文章來源：http://www.zghlxwxcb.cn/news/detail-633937.html
Regular Expressions文章來源地址http://www.zghlxwxcb.cn/news/detail-633937.html
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