日期轉(zhuǎn)化Json異常??
JSON parse error: Cannot deserialize value of type `java.util.Date`
from String \"2022-06-08\": expected format \"yyyy-MM-dd HH:mm:ss\";
nested exception is com.fasterxml.jackson.databind.exc.InvalidFormatException: Cannot deserialize value of type
`java.util.Date` from String \"2022-06-08\": expected format \"yyyy-MM-dd HH:mm:ss\"\n
at [Source: (PushbackInputStream);line: 1, column: 73]
(through reference chain: com.spang.partyManage.party.vo.org.OrgAddAccept[\"creationDate\"])
錯(cuò)誤原因??
不能解析我傳遞的日期數(shù)據(jù)：”2022-06-08“，它默認(rèn)是要這樣的"yyyy-MM-dd HH:mm:ss"。
解決辦法??
直接在數(shù)據(jù)庫對應(yīng)的接受類對象和實(shí)體類對象上加日期轉(zhuǎn)化的注解。
可能由于種種環(huán)境原因，不知道哪個(gè)一定正確，下面三個(gè)注解任選其一。文章來源：http://www.zghlxwxcb.cn/news/detail-580934.html
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern="yyyy-MM-dd", timezone = "GMT+8")
@JsonFormat(pattern = "yyyy-MM-dd")
@JsonField(format = "yyyy-MM-dd" )
private Date creationDate;
補(bǔ)充??
我發(fā)現(xiàn)我公司是用的DateUtil。文章來源地址http://www.zghlxwxcb.cn/news/detail-580934.html
public class DateUtil {
public static final String PATTERN_DATETIME = "yyyy-MM-dd HH:mm:ss";
public static final String PATTERN_DATETIME_MINI = "yyyyMMddHHmmss";
public static final String PATTERN_DATE = "yyyy-MM-dd";
public static final String PATTERN_TIME = "HH:mm:ss";
public static final ConcurrentDateFormat DATETIME_FORMAT = ConcurrentDateFormat.of("yyyy-MM-dd HH:mm:ss");
public static final ConcurrentDateFormat DATETIME_MINI_FORMAT = ConcurrentDateFormat.of("yyyyMMddHHmmss");
public static final ConcurrentDateFormat DATE_FORMAT = ConcurrentDateFormat.of("yyyy-MM-dd");
public static final ConcurrentDateFormat TIME_FORMAT = ConcurrentDateFormat.of("HH:mm:ss");
public static final DateTimeFormatter DATETIME_FORMATTER = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
public static final DateTimeFormatter DATETIME_MINI_FORMATTER = DateTimeFormatter.ofPattern("yyyyMMddHHmmss");
public static final DateTimeFormatter DATE_FORMATTER = DateTimeFormatter.ofPattern("yyyy-MM-dd");
public static final DateTimeFormatter TIME_FORMATTER = DateTimeFormatter.ofPattern("HH:mm:ss");
......
}
使用的時(shí)候：@JsonFormat(pattern = DateUtil.PATTERN_DATE)
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