一:背景
1. 講故事
前些天有位朋友找到我,說(shuō)他的程序跑著跑著就崩潰了,讓我看下怎么回事,其實(shí)沒(méi)怎么回事,抓它的 crash dump 就好,具體怎么抓也是被問(wèn)到的一個(gè)高頻問(wèn)題,這里再補(bǔ)一下鏈接: [.NET程序崩潰了怎么抓 Dump ? 我總結(jié)了三種方案] https://www.cnblogs.com/huangxincheng/p/14811953.html ,采用第二種 AEDebug 的形式抓取即可。
二:Windbg 分析
1. 崩潰原因是什么
如果dump中塞了異常,用 windbg 打開(kāi)的時(shí)候會(huì)有一個(gè)提示 This dump file has an exception of interest stored in it
,輸出如下:
************* Path validation summary **************
Response Time (ms) Location
Deferred SRV*C:\mysymbols*http://msdl.microsoft.com/download/symbols
Symbol search path is: SRV*C:\mysymbols*http://msdl.microsoft.com/download/symbols
Executable search path is:
Windows 7 Version 7601 (Service Pack 1) MP (4 procs) Free x64
Product: Server, suite: Enterprise TerminalServer SingleUserTS
Debug session time: Wed Jun 14 13:34:49.000 2023 (UTC + 8:00)
System Uptime: 0 days 3:28:04.223
Process Uptime: 0 days 0:00:14.000
................................................................
................................................................
......................................................
This dump file has an exception of interest stored in it.
The stored exception information can be accessed via .ecxr.
(9e4.bc4): Stack overflow - code c00000fd (first/second chance not available)
For analysis of this file, run !analyze -v
clr!SlowAllocateString+0x11:
000007fe`f9236451 48c785b0fffffffeffffff mov qword ptr [rbp-50h],0FFFFFFFFFFFFFFFEh ss:00000000`123d5fd0=0000000000000000
從卦中看當(dāng)前有一個(gè) Stack overflow - code c00000fd
異常,說(shuō)實(shí)話好久都沒(méi)看到 棧溢出
了,甚是想念,既然說(shuō)棧溢出了,那就看下異常前是個(gè)啥情況,使用 .excr
即可。
0:028> .excr;k
rax=00000000123d6048 rbx=00000000123d5d70 rcx=0000000000000001
rdx=0000000000000001 rsi=0000000000000000 rdi=00000000123d5880
rip=000007fef9236451 rsp=00000000123d5fb0 rbp=00000000123d6020
r8=00000000ffffffff r9=0000000000000000 r10=00000000123d618e
r11=0000000000000000 r12=0000000000000000 r13=0000000000000000
r14=0000000000000000 r15=0000000000000001
iopl=0 nv up ei pl nz na pe nc
cs=0033 ss=002b ds=002b es=002b fs=0053 gs=002b efl=00010200
clr!SlowAllocateString+0x11:
000007fe`f9236451 48c785b0fffffffeffffff mov qword ptr [rbp-50h],0FFFFFFFFFFFFFFFEh ss:00000000`123d5fd0=0000000000000000
*** Stack trace for last set context - .thread/.cxr resets it
# Child-SP RetAddr Call Site
00 00000000`123d5fb0 000007fe`f920a5bd clr!SlowAllocateString+0x11
01 00000000`123d6050 000007fe`f920a9c7 clr!StringObject::NewString+0x25
02 00000000`123d6080 000007fe`f920a80d clr!Int32ToDecStr+0xdf
03 00000000`123d6320 000007fe`9ab3bb72 clr!COMNumber::FormatInt32+0x10d
04 00000000`123d65f0 000007fe`9ab33e04 0x000007fe`9ab3bb72
05 00000000`123d6630 000007fe`9ab3be52 0x000007fe`9ab33e04
06 00000000`123d6720 000007fe`9ab3bd2a 0x000007fe`9ab3be52
07 00000000`123d6790 000007fe`9ab33e35 0x000007fe`9ab3bd2a
08 00000000`123d67f0 000007fe`9ab3be52 0x000007fe`9ab33e35
09 00000000`123d68e0 000007fe`9ab3bd2a 0x000007fe`9ab3be52
...
ff 00000000`123df860 000007fe`9ab3bd2a 0x000007fe`9ab3be52
從卦中看,當(dāng)前默認(rèn)的 255 個(gè)棧幀全部被打滿(mǎn),看樣子是無(wú)限死循環(huán)了,為了能看到托管部分我們改用 !clrstack
命令。
0:028> !clrstack
OS Thread Id: 0xbc4 (28)
Child SP IP Call Site
00000000123d63b8 000007fef9236451 [HelperMethodFrame_PROTECTOBJ: 00000000123d63b8] System.Number.FormatInt32(Int32, System.String, System.Globalization.NumberFormatInfo)
00000000123d65f0 000007fe9ab3bb72 xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[])
00000000123d6630 000007fe9ab33e04 xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6720 000007fe9ab3be52 xxx_symbol01.xxx_symbol09.xxx_symbol00(Int32, Int32)
00000000123d6790 000007fe9ab3bd2a xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Boolean)
00000000123d67f0 000007fe9ab33e35 xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d68e0 000007fe9ab3be52 xxx_symbol01.xxx_symbol09.xxx_symbol00(Int32, Int32)
00000000123d6950 000007fe9ab3bd2a xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Boolean)
00000000123d69b0 000007fe9ab33e35 xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6aa0 000007fe9ab3be52 xxx_symbol01.xxx_symbol09.xxx_symbol00(Int32, Int32)
00000000123d6b10 000007fe9ab3bd2a xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Boolean)
00000000123d6b70 000007fe9ab33e35 xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6c60 000007fe9ab3be52 xxx_symbol01.xxx_symbol09.xxx_symbol00(Int32, Int32)
00000000123d6cd0 000007fe9ab3bd2a xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Boolean)
00000000123d6d30 000007fe9ab33e35 xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6e20 000007fe9ab3be52 xxx_symbol01.xxx_symbol09.xxx_symbol00(Int32, Int32)
00000000123d6e90 000007fe9ab3bd2a xxx_symbol01.xxx_symbol09.xxx_symbol00(Byte[], Boolean)
....
000000001244db60 000007fe9ab31f0e xxx.PDFFile.xxx_symbol00(System.String, System.IO.Stream, Byte[])
000000001244dbc0 000007fe9ab318e5 xxx.xxx.Convertxxxx(System.IO.Stream, Int32, Int32, System.Drawing.Imaging.ImageFormat, Int32)
從卦中信息看,是代碼用 Convertxxxx
調(diào)用了一個(gè)第三方庫(kù),在這個(gè)庫(kù)中出現(xiàn)了死遞歸。
按理說(shuō)不管外界給了什么參數(shù)下去,都不應(yīng)該用死遞歸的方式來(lái)呈現(xiàn),所以這類(lèi)問(wèn)題可以歸于 SDK 的bug,接下來(lái)我們的研究方向就是看下這個(gè) SDK 是何方神圣?
[assembly: AssemblyCopyright("? 2008 O2 Solutions")]
[assembly: AssemblyProduct("PDFxxx4NET")]
[assembly: AssemblyCompany("O2 Solutions (http://www.xxx.com/)")]
[assembly: AssemblyTrademark("PDFxxx4NET is a trademark of O2 Solutions")]
[assembly: AllowPartiallyTrustedCallers]
[assembly: AssemblyTitle("Print and convert PDF files to images.")]
[assembly: RuntimeCompatibility(WrapNonExceptionThrows = true)]
[assembly: AssemblyDescription("Component for rendering pdf files on .NET platform")]
[assembly: AssemblyConfiguration("")]
[assembly: AssemblyInformationalVersion("2.0.1")]
[assembly: AssemblyKeyName("")]
[assembly: AssemblyDelaySign(false)]
[assembly: CompilationRelaxations(8)]
[assembly: AssemblyVersion("2.0.1.0")]
從卦中看還是 2008 年寫(xiě)的 2.0.1
版本,而官網(wǎng)早已出了 2023 年版本,也就是說(shuō) 15年都沒(méi)有更新,也是厲害,截圖如下:
到這里就可以給到朋友答案了,讓他看下能否把 PDFRender4NET
升級(jí)到最新版本,按理說(shuō)應(yīng)該就沒(méi)有問(wèn)題了。
2. 為什么會(huì)棧溢出
心細(xì)的朋友可能會(huì)有一個(gè)疑問(wèn),既然都棧溢出了,按理說(shuō)異常碼應(yīng)該是 c0000005
(訪問(wèn)違例),怎么會(huì)是 c00000fd
呢?
這是一個(gè)非常好的問(wèn)題,要理解為什么是 c00000fd
而不是 c0000005
,需要你對(duì)棧的布局有一個(gè)比較清晰的理解,為了方便講述,以當(dāng)前的 w3wp 來(lái)繪制一張圖。
畫(huà)完這張圖肯定有朋友會(huì)提幾個(gè)反對(duì)意見(jiàn):
1) 線程棧不是 1M 嗎? 怎么會(huì)是 512k 呢?
這里要說(shuō)的是 1M 并不是什么公理,可以在 PE 頭上隨便設(shè)定的,截圖如下:
2)PAGE_GUARD 不是 1個(gè)內(nèi)存頁(yè)嗎?
很多教科書(shū)都是按 1個(gè)內(nèi)存頁(yè) 講述的,但這也不是定死的,也可能是多個(gè)內(nèi)存頁(yè),比如 2個(gè),5個(gè),要想驗(yàn)證很簡(jiǎn)單,用 !address -f:Stack
觀察下便知。
0:121> !address -f:Stack
BaseAddress EndAddress+1 RegionSize Type State Protect Usage
--------------------------------------------------------------------------------------------------------------------------
0`001f0000 0`00266000 0`00076000 MEM_PRIVATE MEM_RESERVE Stack [~0; 9e4.e30]
0`00266000 0`00268000 0`00002000 MEM_PRIVATE MEM_COMMIT PAGE_READWRITE | PAGE_GUARD Stack [~0; 9e4.e30]
0`00268000 0`00270000 0`00008000 MEM_PRIVATE MEM_COMMIT PAGE_READWRITE Stack [~0; 9e4.e30]
...
0`15710000 0`15788000 0`00078000 MEM_PRIVATE MEM_RESERVE Stack [~139; 9e4.14ac]
0`15788000 0`1578d000 0`00005000 MEM_PRIVATE MEM_COMMIT PAGE_READWRITE | PAGE_GUARD Stack [~139; 9e4.14ac]
0`1578d000 0`15790000 0`00003000 MEM_PRIVATE MEM_COMMIT PAGE_READWRITE Stack [~139; 9e4.14ac]
接下來(lái)我們聊一下什么是 PAGE_GUARD
,從名字上看就是 哨兵頁(yè)
,說(shuō)白一點(diǎn)就是 Windows 做 棧伸展
的一種系統(tǒng)機(jī)制,當(dāng) rsp 訪問(wèn)到這個(gè)區(qū)域時(shí)會(huì)引發(fā)系統(tǒng)的 頁(yè)中斷
進(jìn)而 COMMIT 更多內(nèi)存頁(yè),新的 Commit 頁(yè)會(huì)被 哨兵
侵占,同時(shí)也會(huì)讓渡 RSP 所占的內(nèi)存頁(yè)給程序使用,這是一種良性機(jī)制,一旦 哨兵
無(wú)法侵占更多新的 COMMIT 頁(yè)時(shí),也就表示??臻g已經(jīng)到位了,這時(shí)候會(huì)將自身的 PAGE_GUARD
標(biāo)簽去掉,表示它的使命已完成,如果此時(shí) RSP 訪問(wèn)到了這個(gè)彌留的 哨兵區(qū)
,就會(huì)拋出 c00000fd
異常,這種異常只是表示 RSP 進(jìn)入了 哨兵區(qū)
,不代表??臻g
真的用完了,所以這就是不拋 c0000005
的真正原因,畫(huà)個(gè)簡(jiǎn)圖如下:
說(shuō)了這么說(shuō),如何去驗(yàn)證呢?非常簡(jiǎn)單,我們提取出 StackLimit, StackBase, RSP
即可。
0:028> r rsp
rsp=00000000123d5fb0
0:028> !teb
TEB at 000007fffff70000
ExceptionList: 0000000000000000
StackBase: 0000000012450000
StackLimit: 00000000123d1000
0:028> !address -f:Stack
BaseAddress EndAddress+1 RegionSize Type State Protect Usage
--------------------------------------------------------------------------------------------------------------------------
0`123d0000 0`123d1000 0`00001000 MEM_PRIVATE MEM_RESERVE Stack [~28; 9e4.bc4]
0`123d1000 0`12450000 0`0007f000 MEM_PRIVATE MEM_COMMIT PAGE_READWRITE Stack [~28; 9e4.bc4]
從卦中看,當(dāng)前 哨兵區(qū) = StackLimit ~ StackLimit+0x5000 = 00000000123d1000 ~ 00000000123d6000
,然后看下 rsp=00000000123d5fb0
果然是在這個(gè)范圍內(nèi),在一些低級(jí)語(yǔ)言中還可以繼續(xù)放任 棧溢出
異常,繼續(xù)讓程序跑,當(dāng)代碼跑到圖中的 MEM_RESERVE
區(qū)時(shí)這就是貨真價(jià)實(shí)的 c0000005
訪問(wèn)違例。文章來(lái)源:http://www.zghlxwxcb.cn/news/detail-490062.html
三:總結(jié)
這次崩潰事故主要還是第三方的SDK代碼不健壯導(dǎo)致的 死遞歸
拖累程序崩潰,解決辦法很簡(jiǎn)單,升級(jí)升級(jí)再升級(jí),如果還有問(wèn)題建議提交官方或者使用其他替代品,如果官方解決問(wèn)題不活躍,你還敢用嗎?文章來(lái)源地址http://www.zghlxwxcb.cn/news/detail-490062.html

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